Two concentric circles with radii of 19 and 29 units bound a shaded region. a third circle will be drawn with area equal to that of the shaded area. what must the radius of the third circle be? express your answer in simplest radical form.

Work Shown:

Let P and Q be two concentric circles

P = area of circle with radius 19

P = pi*r^2

P = pi*19^2

P = 361pi

Q = area of circle with radius 29

Q = pi*r^2

Q = pi*29^2

Q = 841pi

R = area of shaded region between circle P and circle Q

R = region outside circle P, but inside circle Q

R = Q - P

R = 841pi - 361pi

R = 480pi

S = area of circle with area equal to region R's area

S = 480pi

S = pi*r^2

pi*r^2 = 480pi

r^2 = 480

r = sqrt(480)

r = sqrt(16*30)

r = sqrt(16)*sqrt(30)

r = 4*sqrt(30)

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

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step-by-step explanation: