O
these are the means and standard deviations for samples of heights from
two kinds of trees.
tree a
mean: 25 ft
standard deviation: 5 ft
tree b
mean: 60 ft
standard deviation: 12 ft
rol
o
.
select the two true statements.
oh
cts
(
dc)
i
a. tree a's heights are less spread out than tree b's heights.
o
b. tree a has a lower average height than tree b.
o
c. tree a's heights are more spread out than tree b's heights.
d tree a has a greater average height than tree b
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The true statements are:

A. Tree A's heights are less spread out than tree B's heights and

B. Tree A has lower average height than tree B

Explanation:

Standard deviation in this case represents the spreading out of heights of the trees, Since tree A has lesser standard deviation given equal to 5 , it is less spread out than B given equal to 12, hence option A. is true.

The average of a quantity is given by mean so, the average height can be compared by the given mean values of the trees. Since, A has lesser mean value (= 25) than B(=60), tree A is said to have lower average height than tree B hence option B. is true.

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3