The tens digit of a two-digit number is 3 less than the units digit. find the original number, if the sum of that number and the number reversed is 143.

The two digit number needed is valued 58.

Given that:

The tens of a two digit number  =  unit's digit - 3

Number reversed  + The number itself = 143

Let the ones digit of that two digit number be x and the tens digit be y. Then by place value concept, we have:

Since the tens digit = unit digit - 3

Thus we have:

or the number is :

Now sum of the number and the number reversed is 143, which means:

Thus, the number is  

Thus, the two digit number needed is valued 58.

Learn more about the sum of digits of a number:

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Let...

x=ones digit

x-3=tens digit

The number in terms of x would be...

10(x-3)+x = 11x-30

The number with its digits reversed would be...

10(x)+x-3 = 11x-3

And...

11x-30+11x-3=143     We can solve for x!

22x=176

x=8

The number would be 58.

58

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: