The sum of three consecutive numbers is eighty-four what is the smallest of the three numbers

Step-by-step explanation:

consecutive numbers are one right after the other...

ur 3 consecutive numbers are :

x and x + 1 and x + 2and they total 84

x + x + 1 + x + 2 = 84combine like terms

3x + 3 = 84

3x = 84 - 3

3x = 81

3x = 81/3

x = 27

x + 1 = 27 + 1 = 28

x + 2 = 27 + 2= 29

so your 3 numbers are 27,28,29 with the lowest being 27

24

Step-by-step explanation: This problem states that the sum of 3 consecutive numbers is 84 and it asks us to find the smallest number.

3 consecutive numbers can be represented as follows.

X ⇒ first number

X + 1 ⇒ second number

X + 2 ⇒ third number

Since the sum of our 3 consecutive numbers is 84, our equation will read X + X + 1 + X + 2 = 84.

Simplifying on the left we get 3x + 3 = 84.

Subtracting 3 from both sides, we have 3x = 81.

Now we can divide both sides by 3 to get x = 27.

This means that 27 will be the smallest number.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation: