Can someone meee

graph y = –4/3x + 1

Step-by-step explanation:

y = -4/3x + 1

in y = mx + b form, the number in the b is the y intercept...so ur y intercept is

(0,1)this is where ur line crosses the y axis

to find ur x axis, sub in 0 for y and solve for x

y = -4/3x + 1

0 = -4/3x + 1

4/3x = 1

x = 1 / (4/3)

x = 1 * 3/4

x = 3/4and ur x intercept is (3/4,0)...this is where ur line crosses the x axis.

in y = mx + b form, the letter m represents ur slopeso ur slope is

-4/3that negative means ur line is descendingso when we graph, we will start at the y int.

go ahead and plot ur intercepts(0,1) and (3/4,0)now look at ur slope -4/3the numerator (either go up or down)the denominator (go right)

if the numerator is negativego downif it was positive u would go up.

so start at (0,1)slope is -4/3so go down 4 and to the right 3...plot that pointthen go down 4 and to the right 3...plot that...ur gonna keep on going down 4 and to the right 3 as far as u need to...connect ur points and u have ur line

if it helps, ur line will be going through points (3,-3), (6,-7),(-3,5), (-6,9)those are some whole number pointsits kinda hard to graph when ur intercepts dont fall on whole numbers

don't know sorry bru

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.