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Mathematics, 21.06.2019 23:30
Solve the following: 12(x^2–x–1)+13(x^2–x–1)=25(x^2–x–1) 364x–64x=300x
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Mathematics, 22.06.2019 00:40
The point (-7, -24) is on the terminal ray of angle 0 which is in standard position. a student found the six trigonometric values for angle e. the student's answers are shown. which value(s) are incorrect? sin(8) cos(8) 24 tan(0) sin(0)=25 cos(0) -- tan(â“¡) - - 24 csc(o)=2 sec(0) --25 cot(6) - za csc(o) sec(0) cot(0) done
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