The weight of people on a college campus are normally distributed with mean 185 pounds and standard deviation 20 pounds. what's the probability that a person weighs more than 200 pounds? (round your answer to the nearest hundredth)

0.23.

Step-by-step explanation:

We have been given that the weight of people on a college campus are normally distributed with mean 185 pounds and standard deviation 20 pounds.

First of all, we will find the z-score corresponding to sample score 200 using z-score formula.

, where,

Z-score,

Sample score,

Mean,

Standard deviation.

Now, we need to find . Using formula  , we will get:

Using normal distribution table, we will get:

Round to nearest hundredth:

Therefore, the probability that a person weighs more than 200 pounds is approximately 0.23.

the probability that a person weighs more than 200 pounds is 0.23

Step-by-step explanation:

Since the weight of people on a college campus are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = weight of people on a college campus

u = mean weight

s = standard deviation

From the information given,

u = 185

s = 20

We want to find the probability that a person weighs more than 200 pounds. It is expressed as

P(x greater than 200) = P(x greater than 200) = 1 - P(x lesser than lesser than or equal to 200).

For x = 200,

z = (200 - 185)/20 = 0.75

Looking at the normal distribution table, the probability corresponding to the z score is 0.7735

P(x greater than 200) = 1 - 0.7735 = 0.23

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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