Construct the graph of the equation y=kx if it is known that the point b belongs to the graph. the graph of which of these two equations goes through point m(−10, 15)?
b(2, −3)
b(3 1/3, -2)
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The graph with B(2,-3) i.e) y= x goes through the point M(-10,15).

Step-by-step explanation:

Consider M(-10,15) and given that equation is y = kx.

Now, substitute M(-10,15) in the equation

⇒ 15 = k × -10

⇒ k = =

⇒ y = x

Now, check with the given points B(2,-3) and B( , -2)

1) B(2,-3)

y = x

⇒(-3) = × 2

⇒ -3 = -3 ⇒ LHS = RHS

⇒ B(2,-3) is the required point.

2) for b( , -2)

LHS ≠ RHS.

So,The graph with B(2,-3) i.e) y= x goes through the point M(-10,15).

me! what did you put for this question?

step-by-step explanation:

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3