The length of a rectangle is 7 feet more than twice the width, and the area of the rectangle is 99 ft.² find the dimensions of the rectangle

Step-by-step explanation:

A = L * W

A = 99

L = 2w + 7

now we sub

99 = (2w + 7)(w)

99 = 2w^2 + 7w

2w^2 + 7w - 99 = 0

(2w - 11)(w + 9) = 0

2w - 11 = 0

2w = 11

w = 11/2

w = 5 1/2 ft (or 5.5 ft) < width is 5 1/2 ft)

L = 2w + 7

L = 2(5.5) + 7

L = 11 + 7

L = 18 ft < length is 18 ft

the answer is d. (1.2, -4.7) on edgn

hope this !

answer: i think it is (1,-2)