Aminister claims that more than 60% of the adult population attends a religious service at least once a month. the null and alternative hypotheses you'd use to test this claim would be:

a. h0 : μ = .6, ha: μ > .6
b. h0 : p = .6, ha: p > .6
c. h0 : p = .6, ha: p ≠ .6
d. h0 : pˆ = .6, ha: pˆ > .6
e. h0 : x = .6, ha: x > .6

d. H0 : pˆ = .6, Ha: pˆ > .6

Step-by-step explanation:

Given that a minister claims that more than 60% of the adult population attends a religious service at least once a month.

Here the subject of interest about a proportion of adult population who attends a religious service at least once a month.

The claim is  this proportion is greater than 60% and we want to check  whether this claim is true.

Hence hypotheses would be for proportion only and not mean.

Since population proportion is to be checked we use p hat

Correct answer is

d. H0 : pˆ = .6, Ha: pˆ > .6

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step-by-step explanation:

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it is x=-4

step-by-step explanation: