Atour company has a ticket price that goes down $2 for every additional person who signs up for a group trip. they charge, per person, 52-2n where n is the number of people that go on the trip. their total revenue, r, as a function of the number of people who can go in the trip is r=52n-2n^2. how many people maximize the revenue for the tour company

13 people will Maximize the revenue for the tour company

Step-by-step explanation:

Data provided in the question:

Revenue function = 52n - 2n²

Now,

To find the point of maxima or minima, differentiating the revenue funtion with respect to the 'n' and equating to zero

⇒ = 0

or

⇒ 52 - 4n = 0

or

⇒ 4n = 52

or

⇒ n = 13

To check for mamixa or minima

again differentiating the revenue function

i.e

= -4     [negative value means the n = 13 is point of maxima ]

Hence,

13 people will Maximize the revenue for the tour company

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.