In many population growth problems, there is an upper limit beyond which the population cannot grow. many scientists agree that the earth will not support a population of more than 16 billion. there were 2 billion people on earth in 1925 and 4 billion in 1975. if is the population years after 1925, an appropriate model is the differential equation
dy/dt=ky(16-y)

note that the growth rate approaches zero as the population approaches its maximum size. when the population is zero then we have the ordinary exponential growth described by y'=16ky. as the population grows it transits from exponential growth to stability.

(a) solve this differential equation.
(b) the population in 2015 will be
(c) the population will be 9 billion some time in the year

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

were is the equation

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

you first to choose the points and then move from then as the slope you have