Luiza is jumping on a trampoline. ht models her distance above the ground (in m) t seconds after she starts

jumping. here, t is entered in radians.

h(t) =-0.6 cos (2pi/2.5)t + 1.5

what is the second time when luiza reaches a height of 1.2 m?

round your final answer to the nearest hundredth of a second.

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H(t)=-0.6cos(2pi/2.5)t+1.5 should be equal to 1.2. If calculated, -0.6cos(0.8pi)t=1.2-1.5 which is equal to -0.6cos(0.8pi)t=-0.3, then cos(0.8pi)t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos(0.8pi)t=cos(pi/3). If simplified, (0.8pi)*t=5pi/3. pi's are cancelled out and t is calculated as 2.08333... If rounded to the nearest hundredth it is 2.08.

2.08 seconds

Step-by-step explanation:

khan academy

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

maybe i can