Miriam is playing a game of dice. for every 1 or 6 rolled, miriam will in $5. for any other number, she must pay $2. how much money can miriam except to win or lose?

So, she can expect to win a total of $0.33 .

Step-by-step explanation:

According to the question miriam will get 5$ when the dice will show 1 or 6 .

And also she will lose 2$ for any other number .

Now ,

Total number of favorable cases for winning of 5$ for the miriam are 2.

Total number of cases = 6.

Also,

Total number of cases in which she will lose money will be 4.

So, probability of win = .

Probability of loss = .

Thus ,

Total amount of money that she can expect to win =

×5 - ×2 = .

So, she can expect to win a total of $0.33 .

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

answer: idk

step-by-step explanation: