Which statements about triangle jkl are true? select two options.

m is the midpoint of line segment kj.

n is the midpoint of line segment jl.

mn = one-halfkj

mn = 4.4m

mn = ml

2nd and 3rd statement

Step-by-step explanation:

From the diagram, the 1st statement is wrong, the 2nd statement is correct

To know which of the rest of the statement is correct we have to find the value of MN

So we use the cosine rule to find the angle inside the triangle at point L

c2 = a2+b2-2abcosC

For our triangle

c= 12.8

b= 5.9+5.9=11.8

a= 3.7+3.7=7.4

C = ?

(12.8)2 = (7.4)2 + (11.8)2 - 2x11.8x7.4cosC

163.84 = 54.76+739.24 - 174.64cosC

163.84 = 194 - 174.64cosC

163.84-194 = -174.64cosC

-30.16 = -174.64cosC

-30.16/-174.64 =cosC

cosC = 0.1727

cos-1(0.1727) = 80.06

C = 80.06 degrees

So we use this value to find length MN with also cosine rule from the triangle NML

c2 = a2+b2-2abcosC

c = ?

a = 5.9

b = 3.7

C = 80.06

c2 = (5.9)2 + (3.7)2 - 2x5.9x3.7cosC

c2 = 34.81 + 13.69 - 43.66x0.1727

c2 = 48.5 - 7.54

c2 = 40.96

c = root(40.96)

c = 6.4

Which is half of KJ

So therefore, the third statement is correct

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!