The graphs of y=x-3 and y = 3x -4 intersect at
approximately
1) (0.38,-2.85), only
| 2) (2.62,3.85), only
3) (0.38,-2.85) and (2.62,3.85)
4) (0.38, -2.85) and (3.85,2.62)

Option 3) (0.38,-2.85) and (2.62,3.85)

Step-by-step explanation:

The correct question is

The graphs of y=x^2-3 and y=3x-4 intersect at approximately...

we have

----> equation A

----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

Equate equation A and equation B

The formula to solve a quadratic equation of the form

is equal to

in this problem we have

so

substitute in the formula

so

Find the values of y (substitute the value of x in equation A or equation B)

For x=2.62 ---->

For x=0.38 ---->

therefore

The intersection points are approximately  (0.38,-2.85) and (2.62,3.85)

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi