Arectangle has a length that is one foot less than twice its width. it the area of the rectangle is 91 square feet then which of the following equations could be used to solve for its the width of the rectangle?

Step-by-step explanation:

Well.. First of all, the question says that we are working with a rectangle..

So, the rectangle has a length and width. I'll call them L and w.

Look at this phrase: " length that is one foot less than twice its width"

it means, in a algebraic language: L = 2w - 1

Let's analysis the next phrase: "it the area of the rectangle is 91 square feet"

So, A = 91 ft²

But you have to remember that the rectangle area is a product of L and w.

L x w = 91

They are the following equations that you could be used to solve the system of equations.

Now, you have a system of equations and I suggest you to solve it using the substituition method.

L = 2w - 1

L x w = 91

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

answer: i think one of the answer is $150 and $300?

step-by-step explanation: