What will be the difference in volume of a cylinder if the radius is doubled?

Explanation:

V1 = volume of first cylinder

V1 = pi*(radius)^2*(height)

V1 = pi*r^2*h

V2 = volume of second cylinder with doubled radius

V2 = pi*(new radius)^2*(height)

V2 = pi*(2r)^2*h

V2 = pi*(4r^2)*h

V2 = 4pi*r^2*h

V3 = difference in volumes

V3 = V2 - V1

V3 = 4pi*r^2*h - pi*r^2*h

V3 = 4pi*r^2*h - 1pi*r^2*h

V3 = (4-1)pi*r^2*h

V3 = 3pi*r^2*h

3pir^2h.

Step-by-step explanation:

Initial volume = pi r^2 h

New volume = pi (2r)^2 h

= 4pir^2h

Difference = 3pir^2h.

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value