Astudy was conducted to determine whether an expectant mother’s cigarette smoking has any effect on the bone mineral content of her otherwise healthy child. a sample of 78 newborns whose mothers smoked during pregnancy has mean bone mineral content ! = 0.089g/cm and standard deviation ! = 0.022g/cm; a sample of 115 infants whose mothers did not smoke has mean ! = 0.083g/cm and standard deviation ! = 0.023g/cm. assume that the underlying population variances are equal. a) are the two samples of data paired or independent? b) state the null and alternative hypotheses of the two-sided test. c) conduct the test at the 0.05 level of significance. what do you conclude?

a) The samples are independent

b) : mu1=mu2*

   : mu1≠mu2

c) There is no significant evidence that an expectant mother’s cigarette smoking has any effect on the bone mineral content of her otherwise healthy child

Step-by-step explanation:

Newborns whose mothers smoked during pregnancy and whose didn't smoke are two different populations. Therefore the samples are independent.

* Let mu1 be the mean bone mineral content of newborn babies whose mothers smoked during pregnancy

Let mu2 be the mean bone mineral content of newborn babies whose mothers didn't smoke during pregnancy

Null and alternative hypotheses are:

Test statistic can be found using the equation:

where

≈1.825

two tailed p-value of test statistic is  0.068. Since 0.068>0.05, we fail to reject the null hypothesis. There is no significant evidence that an expectant mother’s cigarette smoking has any effect on the bone mineral content of her otherwise healthy child

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

-2/