For women aged 18-24, systolic blood pressures (in mm hg) are normally distributed with a mean of 114.8 and a standard deviation of 13.1. if 23 women aged 18-24 are randomly selected, find the probability that their mean systolic blood pressure is between 119 and 122. your answer should be a decimal rounded to the fourth decimal place.

5.77% probability that their mean systolic blood pressure is between 119 and 122.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , a large sample size can be approximated to a normal distribution with mean and standard deviation .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Find the probability that their mean systolic blood pressure is between 119 and 122.

This is the pvalue of Z when X = 122 subtracted by the pvalue of Z when X = 119. So

X = 122

has a pvalue of 0.9959

X = 119

has a pvalue of 0.9382

So there is a 0.9959 - 0.9382 = 0.0577 = 5.77% probability that their mean systolic blood pressure is between 119 and 122.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204