The article "chances are you know someone with a tattoo, and he's not a sailor" included results from a survey of adults aged 18 to 50. the accompanying data are consistent with summary values given in the article. at least one tattoo no tattoo age 18–29 190 310 age 30–50 60 440 assuming these data are representative of adult americans and that an adult american is selected at random, use the given information to estimate the following probabilities. a) p(tattoo)b) p(tattoo|age 18-29)c) p(tattoo|age 30-50)d) p(age 18-29|tattoo)

a) 0.25

b) 0.38

c) 0.12

d) 0.64

Step-by-step explanation:

We have these following informations.

There are 500 people between 18 and 29. Of those 190 have at least one tattoo and 310 have no tattoo.

There are also 500 people between 30 and 50. Of those, 60 have at least one tattoo and 440 have no tattoo.

a) P(tattoo)

There are 1000 people. Of those, 190+60 = 250 have tattoo. So P(tattoo) = 250/1000 = 0.25.

b) P(tattoo|age 18-29)

There are 500 people aged 18-29. Of those, 190 have at least one tattoo. So P(tattoo|age 18-29) = 190/500 = 0.38.

c) P(tattoo|age 30-50)

There are 500 people aged 18-29. Of those, 60 have at least one tattoo. So P(tattoo|age 30-50) = 60/500 = 0.12.

d) P(age 18-29|tattoo)

250 people have at least one tattoo. Of those, 160 are between 18 and 29. So P(age 18-29|tattoo) = 160/250 = 0.64.

your answer is the frist one

hop i

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629