Frank's painting is on a large triangular canvas with side lengths 4 meters,
5 meters and 7 meters, as shown. he wants to create a frame such that its inner
border is flush with each side of the canvas and every point on its outer border
is a distance of exactly 2 cm from the closest point on the canvas. in square
centimeters, what is the area of the frame? express your answer to the nearest
whole number
4 m
5
m

Step-by-step explanation:

The triangle is attached.

According to the problem, the inner frame is 2 cm wide.

To find the area of that inner frame, we just have to subtract the outer triangle area with the inner triangle area.

Now, we know that the outer part of the triangular canvas has dimensions of 4m, 5m and 7, which are equivalent to 400cm, 500cm, and 700cm, because 1 meter is 100 centimeters.

Now, the area of the other triangle is

Where is half the perimeter. So, if the perimeter is

And are the sides of the triangle.

Replacing all these value, we have

Then, we do the same process, but in this case, the inner canvas has dimensions of 398cm, 498cm and 698 cm.

So, the perimeter is

And the area would be

So, the area of the frame is

i believe the answer to be 48

step-by-step explanation: