Mr. schwartz builds toy cars. he begins the week with a supply of 85 wheels, and uses 4 wheels for each car he builds. mr. schwartz plans to order more wheels once he has fewer than 40 wheels left.

When will he have less than 40 wheels left? Well you can make the equation...

85-4x=40

And then solve for x.

85-4x=40

-4x=-45

x=11 1/4 rounded up to 12

He will have less than 40 wheels left after he has built 12 cars.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8