There are 130 people in a sport centre. 61 people use the gym. 68 people use the swimming pool. 60 people use the track. 25 people use the gym and the pool. 30 people use the pool and the track. 19 people use the gym and the track. 6 people use all three facilities. a person is selected at random. what is the probability that the person uses exactly one of the facilities?

Explanation:

As shown in the Venn diagram,

Let

U=[The total number of people in the sport center ]

This implies that

n(U)=130

G=[Those who use the gym]

This implies that

n(G)=61

P=[Those who use the pool]

This implies that

n(P)=68

T=[Those who use the track]

This implies that

n(T)=60

a=those who use only the gym

b=those who use only the pool

c=those who use only the track

From the digram,

a=61-(13+6+19)=61-38=23

b=68-(6+24+19)=68-49=19

c=60-(13+6+24)=60-43=17

The number of people who use exactly one facilities=a+b+c=23+19+17=59

Hence, the probability that a person selected at random uses exactly one the facilities

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)