Afamily has three children. using b to stand for a boy and g for girl give the following.(to indicate that the first child is a boy, the second child is a boy, and the third child is a girl enter bbg. enter your answers as a comma-separated let the event e that the family has exactly two boys.

a) find the probability p(e)
b) find the odd o(e) part a): [select ] part b): iselect ) ?

3/8 and 3/5

Step-by-step explanation:

Given that a family has three children. Using b to stand for a boy and g for girl give the following we can write sample space for a family having three children as

(bbb, bbg, bgg, bgb, gbb, gbg, ggb, ggg)

E - exactly two boys

Sample space count = 8

Exactly two boys count = 3

a) p(E) =

b) odds for E is probability/1-probability

=

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent