Store 1 earned 10% of the money invested i it while store 2 lost 8% of the amount invested in it. the net total gain was $1,300. this year the respective quantities were +6%, +%5 and $2,250. find the merchants investment for each store

Store 1= $150

Store 2= $250

Step-by-step explanation:

Let the amount invested by store 1 be x while store 2 be y hence

10x-8y=1300 Eqn 1

Make x the subject of the formula for the first equation

10x=1300+8y divide both sides by 10

X=130+0.8y

6x+5y=2250 Eqn 2

Substituting where there’s x with 130+0.8y in equation 2 we obtain

6(130+0.8y)+5y=2250

780+4.8y+5y=2250

9.8y+780=2250

9.28y=2250-780=1470

Y=1470/9.8=150

X=130+0.8y= 130+0.8(150)=250

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

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step-by-step explanation:

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