Four students have a plan for a movie night where they have three options, movie a, movie b, movie c. they decide that they would not let any individual go for the movie along , what’s the number of all possible plans ?

Total number of possible plans = 9

Step-by-step explanation:

Four students have a plan for a movie night where they have three options, movie A, movie B, movie C. They decide that they would not let any individual go for the movie alone.

So they can go in two groups of 2 or in a group of 4.

If they go in two groups of 2 ,the possible cases are selecting any 2 movies out of the 3 and also selecting which group sees which movie.

So total cases = 3 2 = 6

If they all go as a group there are only 3 cases as they can go for any of the movie.

So the total number of cases = 6 + 3 = 9

a

step-by-step explanation:

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answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.