Delia has $945 in 20 dollar and 5 dollar bills. she finds she has 5 times as many 20 dollar bills as 5 dollar bills
a)writing x as the number of 20 dollar bills form an equation to show the info
b)solve the equation to find the number of bills of each type delia has

a) 20x + x = 945

b) Delia has 45 $20 bills and 9 $5 bills.

Step-by-step explanation:

a)

Let x = number of $20 bills.

"she finds she has 5 times as many 20 dollar bills as 5 dollar bills"

Since she has 5 times as many $20 bills as $5 bills, that means the number of $5 bills is 1/5 number of $20 bills.

The number of $5 bills is 1/5 of x, or x/5.

x number of $20 bills are worth 20x. x/5 number of $5 bills are worth 5 * x/5, or x. The total worth of her bills is 20x + x.

The total worth of her bills is $945.

That means that 20x + x must equal $945. That gives us the equation:

20x + x = 945

b)

20x + x = 945

21x = 945

Divide both sides by 21.

x = 45

x is the number of $20 bills, so she has 45 $20 bills.

The number of $5 bills is 1/5 the number of $20 bills.

1/5 of 45 is 9. She has 9 $5 bills.

Delia has 45 $20 bills and 9 $5 bills.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted