The formula used to compute a confidence interval for the mean of a normal population when n is small is the following.

x^^\_ +/-\(t text( critical value)\)s/sqrt(n)

what is the appropriate t critical value for each of the following confidence levels and sample sizes? (round the answers to two decimal places.)

(a) 90% confidence, n = 17

(b) 90% confidence, n = 12

(c) 99% confidence, n = 24

(d) 90% confidence, n = 25

a)

b)

c)

d)

Step-by-step explanation:

We are given the following information in the question:

Confidence interval:  

We have to find the appropriate t critical values for each of the following confidence levels and sample sizes:

a) 90% confidence, n = 17

Degree of freedom = n - 1 = 16

b) 90% confidence, n = 12

Degree of freedom = n - 1 = 11

c) 99% confidence, n = 24

Degree of freedom = n - 1 = 23

d) 99% confidence, n = 25

Degree of freedom = n - 1 = 24

you would need to know all the numbers that are on there

step-by-step explanation:

.19875994384

step-by-step explanation:

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