in the figure below, ∠dec ≅ ∠dce, ∠b ≅ ∠f, and df congruent to bd. point c is the point of intersection between ab and bd while point e is the point of intersection between ag and df. prove δabc ≅ δgfe.

what i have right now is;
∠b ≅ ∠f given
cb ≅ ef df ≅ bd, (given), df - ed ≅ bd - cd

i'm trying to prove ∠dce ≅ ∠acb and ∠dec ≅ ∠gef so that i can use asa to prove δabc ≅ δgfe, but i don't know how to do that and this is very urgent so

answer:

its a

step-by-step explanation:

answer:

(ex: a = b and b = c, then a = c) ab//cd and p is any point. prove that angle abp+angle bpd + angle cdp=360^0. (the fig. in the figure below, ∠dec ≅ ∠dce, ∠b ≅ ∠f, and segment df is congruent to segment bd. point c is the point of intersection between segment ag and segment bd, while point e is the point of .

step-by-step explanation:

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

the answer to this is a. a^2 + b^2 = c^2