Suppose that the distance an aircraft travels along a runway before takeoff is given by d=(5/3)t^2, where d is measured in meters from the starting point and it measured in seconds from the time the brakes are released. the aircraft will become airborne when its speed reaches 300km/h. how long will it take to become airborne, and what distance will it travel in that time?

It will take 90s for the aircraft to become airbone.

In that time, the aircraft will have traveled 13500m = 13.5km.

Step-by-step explanation:

The velocity function is the derivative of the distance function.

In this problem, we have the following distance function:

So the speed function is the following:

The aircraft will become airborne when its speed reaches 300km/h. How long will it take to become airborne?

This is going to happen when S(t) = 300. So:

It will take 90s for the aircraft to become airbone.

What distance will it travel in that time?

This is D(t) when t = 90. So:

In that time, the aircraft will have traveled 13500m = 13.5km.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi