The volume v of a cylinder is computed using the values 8.8m for the diameter and 5.8m for the height. use the linear approximation to estimate the maximum error in v if each of these values has a possible error of at most 8%.

The maximum error is approximately Ev=24%

Step-by-step explanation:

the volume of the cylinder V is

V= π/4*H*D²

where H= height and D= diameter

the variation of V will be

dV = (∂V/∂H)*dH + (∂V/∂D)*dD

dV = π/4*D²*dH  +π/2*H*D*dD

if we divide by the volume V

dV /V  = (π/4*D²*dH  +π/2*H*D*dD )/( π/4*H*D²) = dH/H + 2*dD/D

dV /V =  dH/H + 2*dD/D

then we can approximate

error in V= Ev= ΔV/V ≈ dV/V

error in H= Eh=ΔH/H ≈ dH/H

error in D= Ed=ΔD/D ≈ dD/D

thus

Ev= Eh + 2*Ed

since Ed=Eh=E=8%

Ev=  Eh + 2*Ed =3*E=3*8%=24%

Ev= 24%

therefore the maximum error is approximately Ev=24%

the correct answer is x/3+10≥32

hope this !

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step-by-step explanation:

u take $30 minus $24. the answer/original($30)