The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. let r be the mean delivery time for a random sample of 40 orders at this restaurant. calculate the mean and standard deviation ofx round your answers to two decimal places. mean of rd t' minutes standard deviation of 2 minutes

estimated sample mean X is 14.7 minutes

sample standard deviation is ≈ 0.59 minutes.

Step-by-step explanation:

Let X be the mean delivery time for a random sample of 40 orders at this restaurant, then

X can be estimated as 14.7 minutes (mean delivery time for all food orders at a fast-food restaurant during the lunch hour)

Let s be the standard deviation of delivery time for a random sample of 40 orders at this restaurant, then

≈ 0.59 where

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

$650 per month plus utilities

step-by-step explanation:

just based on the info you gave, it would seem more cost effective to rent at $650 per month plus utilities.   if utilities are, in fact, $150 per month, your monthly living costs would be $800 as opposed to the other option of $825.