Astudent reports that, of a simple random sample of 50 college u undergraduate students, 21 % were taking more than fifteen credit hours we know that the student has made mistake (or maybe really did not conduct the survey). why? a) there are . 5 0 students in the sample, so percentages should be multiples of 2% b) there are 50 students in the sample, so percentages should be multiples of 0.02% c) d) 21% of 50 students is 10.5 students, and you cannot sample a fraction of a student. both a and c are correct. e) both b and c are correct

D) Both A and C are correct.

Step-by-step explanation:

If the sample contains 50 students, the percentage equivalent to each student is:

Each student corresponds to 2%, which means that percentages should be multiples of 2%.

21% is not a multiple of 2% and corresponds to:

21% of 50 students is 10.5 students, and you cannot sample a fraction of a student.

Therefore, Both A and C are correct.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

y=x+9

?

step-by-step explanation: