Arecent study focused on the number of times men and women send a twitter message in a day. the information is summarized here. sample size - sample mean - population standard deviation men: 25 - 23 - 5 women: 30 - 28 - 10 at the 0.01 significance level, we ask if there is a difference in the mean number of times men and women send a twitter message in a day. what is the value of the test statistic for this hypothesis test?

There is no difference in the mean number of times men and women send a Twitter message in a day

Zmen = 0.4

Zwomen = 0.2

Step-by-step explanation:

Null hypothesis: There is no difference in the mean number of times men and women send a Twitter message in a day

Alternate hypothesis: There is a difference in the mean number of times men and women send a Twitter message in a day

Z = (sample mean - population mean)/(sd ÷ √n)

Zmen = (25 - 23)/(5÷√1) = 2/5 = 0.4

Zwomen = (30 - 28)/(10÷√1) =2/10= 0.2

For a two tailed test, at 0.01 significance level, the critical value is 2.576

0.2 and 0.4 falls within the region bounded by -2.576 and 2.576, so we fail to reject the null hypothesis

There is no difference in the mean number of times men and women send a Twitter message in a day

54

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.