Acompany makes two different-sized ice cream cones. the smaller cones are 3.5 inches tall and have a diameter of 3 inches. the larger cones are 5.1 inches tall and have a diameter of 4.5 inches. abour how much greater, to the mearest tenth of a cubic inch, is the volume of the larger cone than the volume of the smaller cone?

show your work.

The Volume of large cone is  19.545 greater than the smaller cone

Step-by-step explanation:

Given:

Size of the small cone =  3.5 inches

Diameter of the small cone  = 3 inches

Size of the large cone =  3.5 inches

Diameter of the small cone  = 3 inches

To Find:

How much greater, to the nearest tenth of a cubic inch, is the volume of the larger cone than the volume of the smaller cone = ?

Solution:

Volume of the small cone :

Radius =

Radius =

Radius = 1.5 inches

volume of the cone  =

substituting the values,

=>

=>

=> 16.485

Volume of the large cone :

Volume of the large cone :

Radius =

Radius =

Radius = 2.25 inches

volume of the cone  =

substituting the values,

=>

=>

=>36.06

Now ,

volume of small cone - volume of large cone

=>36.06 - 16.485

=>19.545

The volume of the larger cone is 18.8 sq.inches more than the volume of the smaller cone.

Step-by-step explanation:

Height of smaller cone = 3.5 inches

Diameter of smaller cone = 3 inches

Radius of smaller cone =

Volume of smaller cone =

Height of larger cone = 5.1 inches

Diameter of larger cone = 4.5 inches

Radius of larger cone =

Volume of larger cone =

Difference in volumes = 27.048-8.25=

Difference in volumes to nearest tenth =

So, the volume of the larger cone is 18.8 sq.inches more than the volume of the smaller cone.

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5