Mr. verma has an orchard of length and breadth 280m and 200m respectively. he wants to fence it with 4 rounds of barbed wire. find the cost of fencing at ₹35 per metre.

₹ 109.71

Step-by-step explanation:

Perimeter of orchard:

P = 2(l + b)

P = 2(280 + 200)

P = 2(480)

P = 960 m

4 rounds of barbed wire:

960 × 4 = 3,840 m

₹35 per meter.

Cost:

3840 ÷ 35 = 109.71

answer: the answer is 35%

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.