Two buses leave towns 1015 miles apart at the same time and travel toward each other. one bus travels 11 miles/hr slower than the other. if they meet in 7 hours, what is the rate of each bus?

Step-by-step explanation:

Bus One

speed = x

t = 7 hours

d = ?

Bus two

speed = x + 11

time = 7 hours

d1 = 1015 miles - d

Equations

d = s * t

Bus 1 + bus 2 = 1015

Solution

x * 7 + (x + 11)*7 = 1015

7x + 7x + 11*7 = 1015

14x + 77  =1015

14x + 77 - 77 = 1015 -  77

14x = 938

14x/14 = 938/14

x = 67 miles / hour

x + 11 = 78 miles / hour