You have to spend money to make money ! you purchase a mix of newspaper ads and online ads. each newspaper ad cost $18.50 and each social media ad cost $26.50. you purchase a total of 24+ and you spend a total of $588 on advertising. how many of each type of ads do you buy?

You buy six newspaper ads & eighteen social media ads.

Step-by-step explanation:

First, we change ads into variables to be more easier to calculate :

Let newspaper = x

Let social media = y

Second, make this variables into an equation, given that you purchase a total of 24 ads :

x + y = 24 (first equation)

Next, given that x = $18.50 & y = $26.50 & spent a total of $588 so you can make another equation :

18.50x + 26.50y = 588 (second equation)

Now, solve this simultaneous equation using elimination or substitution (depends on you) :

substitution =>

x + y = 24 (1)

18.50x + 26.50y = 588 (2)

(1)=> y = 24 - x (3)

(3)=>(2) 18.5x + 26.5(24-x) = 588

18.5x + 636 - 26.5x = 588

-8x = -48

x = 6

sub x=6 into(3)

(3)=> y = 24 - 6

= 18

newspaper = x

= 6

social media = y

= 18

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

i dont know

step-by-step explanation: