There are five nickels, five dimes and five quarters in your pocket. you randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter

The question is incomplete, this is the complete question.;

There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.

The answer to the question is;

the probability of this occurring is 1/27

Step-by-step explanation:

Let n(N) =5 ( the number of nickels)

n(D) =5 ( the number of dimes) and

n(Q) = 5 ( the number of quarters)

P(N)= 5/15=1/3 (prob of picking a nickel)

P(D) =5/15=1/3 (prob of picking a dime)

P(Q) = 5/15= 1/3 (prob of picking a quatre)

The probability of picking the three= P(N)×P(D)×P(Q)

= 1/3×1/3×1/3

= 1/27

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.