11.d is a point on the side of triangle abc, such that angleadc=anglebac. show that ca^2=cb. cd

Question is Incomplete,Complete Question is below.

D is a point on the side BC of a triangle ABC such that angle ADC = angle BAC Show that CA square=CB .CD

The Proof is given below.

Step-by-step explanation:

Given:

In ΔABC,

∠ADC = ∠BAC

To Show:

Proof:

In ΔBAC and ΔADC

∠ADC = ∠BAC ............................Given

∠C = ∠C .....................................Reflexive Property

∴ ΔBAC ~ ΔADC .................... A-A similarity test

If two triangles are similar then their sides are in proportion.

..........Proved

answer is 67%

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.