The constraints of a problem are graphed below. what are the vertices of the feasible region?

(0, 0), (0, 15), (20, 25), (40, 0)

(0, 0), (0, 40), (25, 20), (15, 0)

(0, 15), (20, 25), (40, 0)

(0, 40), (25, 20), (15, 0)

(0, 0), (0, 15), (20, 25), (40, 0)

Step-by-step explanation:

The diagram shows shaded region in the form of quadrilateral bounded with two given lines and x- axis and y-axis. Four vertices of this quadrilateral are point of intersection of those lines or lines with coordinate axes.

The first vertex of this quadrilateral lies at the origin (point of intersection of two axes), then its coordinates are (0,0).

The second vertex lies on the x-axis and its coordinates are (40,0) (placed at 40 on the x-axis)

The third vertex lies on the y-axis and its coordinates are (0,15) (placed half way between 10 and 20 on the y-axis).

The fourth vertex is the intersection of two lines. Its coordinates are (20,25) (draw vwrtical line from this vertex t x-axis, it will intersect x-axis at 20, draw horizontal line to y-axis, it will intersect the y-axis at 25).

So, correct option is A: (0, 0), (0, 15), (20, 25), (40, 0)

(0, 0), (0, 15), (20, 25), (40, 0)

Step-by-step explanation:

The feasible region is the shaded area in the graph. This region has four vertices which are:

(0, 0) at the bottom left

(0, 15) at the top left

(20, 25) at the top center

(40, 0) at the bottom right

Note: the points have the notation (x, y)

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option