What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^ 2-4}\right) dx d ( 3x 2 −4 2x+3 )start fraction, d, divided by, d, x, end fraction, (, start fraction, 2, x, plus, 3, divided by, 3, x, squared, minus, 4, end fraction, )at x=-1x=−1x, equals, minus, 1 ?

4.

Step-by-step explanation:

We are asked to find the value of expression at .

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

Therefore, our required derivative is .

Now, we will substitute in our derivative to find the required value as:

Therefore, the value of expression at is 4.

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step-by-step explanation: