Would the margin of error be larger or smaller for 80% confidence? explain.
a. to be less confident, the interval needs to contain the true proportion more often, so the margin of error would be smaller.
b. to be less confident, the interval needs to contain the true proportion more often, so the margin of error would be larger.
c. to be less confident, the interval needs to contain the true proportion less often, so the margin of error would be smaller.
d. to be less confident, the interval needs to contain the true proportion less often, so the margin of error would be larger.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}