Itruly need on 1 and 2 having a hard time with these

6 and 3

Step-by-step explanation:

The Fundamental Theorem of Algebra states.

A polynomial of degree n has n roots.

(1)

This is a polynomial of degree 6 and has 6 roots

(2)

f(x) = (x + 3)(2x - 1)²

     = (x + 3)(4x² - 4x + 1)

     = 4x³ - 4x² + x + 12x² - 12x + 3

     = 4x³ + 8x² - 11x + 3

This is a polynomial of degree 3 and has 3 roots

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

t hope this

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