When the air temperature is a constant 70f, an object cools from 170f to 140f in one half-hour. what is the temperature of this object after 1 hour? equation: t(t)=ts+(to-ts)e^(-kt)

27 +27 or 27times 2=54

the diffrence is 0

just took the test and my answers down below!

step-by-step explanation:

check the pic :

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5