Two professors at a local college developed a now teaching curriculum designed to increase students' grades in math classes. in a typical developmental math course, 45% of the students complete the course with a letter grade of a, b, or c. in the experimental course, of the 20 students enrolled, 18 completed the course with a letter grade of a, b, or c. is the experimental course effective at the alpha = 0.05 level of significance? identity the correct null and alternative hypotheses. h_0: p = 0.45 versus h_1: p > 0.45 determine the p-value. p-value = (round to three decimal places as needed.)

We can conclude that the experimental course effective at the alpha = 0.05 level of significance.

Step-by-step explanation:

Let p be the proportion of students from experimental course who complete the course with a letter grade of A, B, or C. Null and alternative hypotheses are:

H_0: p = 0.45

H_1: p > 0.45

Test statistic can be found using the equation

where

Then ≈4.045

Since the one tailed 19 degrees of freedom p-value is ≈0.0003<0.05 we can conclude that the experimental course effective at the alpha = 0.05 level of significance.

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

-60.75

step-by-step explanation:

just add the numbers then put the negative sign on it