Two objects are moving along separate linear paths where each path is described by position, d, and time, t. the variable d is measured in meters, and the variable t is measured in seconds. the equation describing the graph of the position of the first object with respect to time is d = 2.5t + 2.2. the graph of the position of the second object is a parallel line passing through (t = 0, d = 1). what is the equation of the second graph?

it would start at 2.2 on the y axis and go up 2.5 and over 1

Step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.