Maria invested a total of 31,000 in two account, first account earned a rate of 14%. how ever second account suffer a 10% loss in the same time. at the end of one year the total amount money gain 1,700. how much was invested in school account

the amount of money that Maria invested in the first account is $20000

the amount of money that Maria invested in the second account is $11000

Step-by-step explanation:

Let x represent the amount of money that Maria invested in the first account.

Let y represent the amount of money that Maria invested in the second account.

Maria invested a total of 31,000 in the two account. This means that

x + y = 31000

The first account earned a rate of 14%. This means that the amount earned on the first account is 14/100×x = 0.14x

However, the second account suffered a 10% loss in the same time. This means that the amount lost is

10/100×y = 0.1y

At the end of one year the total amount money gain 1,700. This means that

0.14x - 0.1y = 1700 - - - - --1

Substituting x = 31000 - y into equation 1, it becomes

0.14(31000 - y)- 0.1y = 1700

4340 - 0.14y - 0.1y = 1700

- 0.14y - 0.1y = 1700 - 4340

-0.24y = -2640

y = 2640/0.24 = 11000

x = 31000 - y = 31000 - 11000

x = 20000

incomplete question. how do you expect anyone to you when you do not post the question in its entirety?

lol we need to see what the question is asking about

step-by-step explanation: