Brent has a shopping bag with 8 similar size containers of yogurt: 2 strawberry, 3 cherry, and 3 raspberry. if he randomly takes 2 yogurt containers from the bag
without replacement, what is the probability that neither will be strawberry yogurt?

Step-by-step explanation:

Number of strawberry = 2

Number of cherry = 3

Number of  = 3

Total number = 8

Brent randomly takes 2 yogurt containers from the bag

without replacement ,we are to find the probability that hat neither will be strawberry yogurt.

Let r represent  raspberry and c represents  Cherry ,then Bent selection could be :

{ rr , cc , rc , cr}

Calculating this , we have

( x   ) + ( x   ) + ( x   ) + ( x   )

=

= 15/28

Therefore , the probability that neither will be strawberry yogurt= 15/28

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this